Расшифровать JavaScript

Обсуждение в разделе «PHP, PERL, MySQL, JavaScript», начал(-а) SashaSashaSasha, 19.03.2017.

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  1. SashaSashaSasha

    SashaSashaSasha New Member

    Регистрация:
    19.03.2017
    Сообщения:
    1
    Одобрения:
    0
    Репутация:
    0
    Добрый день, необходимо расшифровать один JavaScript , а именно
    Code:
    eval((function() {
        var y = [70, 81, 89, 90, 65, 86, 85, 71, 88, 76, 66, 87, 75, 94, 72, 80, 60, 82, 79, 74];
        var r = [];
        for (var c = 0; c < y.length; c++) r[y[c]] = c + 1;
        var x = [];
        for (var l = 0; l < arguments.length; l++) {
            var n = arguments[l].split('~');
            for (var u = n.length - 1; u >= 0; u--) {
                var h = null;
                var b = n[u];
                var z = null;
                var e = 0;
                var s = b.length;
                var t;
                for (var o = 0; o < s; o++) {
                    var m = b.charCodeAt(o);
                    var k = r[m];
                    if (k) {
                        h = (k - 1) * 94 + b.charCodeAt(o + 1) - 32;
                        t = o;
                        o++;
                    } else if (m == 96) {
                        h = 94 * (y.length - 32 + b.charCodeAt(o + 1)) + b.charCodeAt(o + 2) - 32;
                        t = o;
                        o += 2;
                    } else {
                        continue;
                    }
                    if (z == null) z = [];
                    if (t > e) z.push(b.substring(e, t));
                    z.push(n[h + 1]);
                    e = o + 1;
                }
                if (z != null) {
                    if (e < s) z.push(b.substring(e));
                    n[u] = z.join('');
                }
            }
            x.push(n[0]);
        }
        var i = x.join('');
        var f = 'abcdefghijklmnopqrstuvwxyz';
        var w = [42, 126, 96, 39, 10, 92].concat(y);
        var d = String.fromCharCode(64);
        for (var c = 0; c < w.length; c++) i = i.split(d + f.charAt(c)).join(String.fromCharCode(w[c]));
        return i.split(d + '!').join(d);
    })('var _$_64e7=["hash","FU","getElement@qyId","pFc","FUvar","pFcvarFGst","href","attrFGn1FGst-2FGn2F$ststF[showdecor","background",FBreview-st.jFNcssF]revF1st.jFN#selF1st-baFV.jFN#sel.baFV","active","addClassFGn","left","right","removeClass","li","parentF]cmfFP","show",FSneFbF`ordFTdFPdFGandarFbstnd","slow","fadeInFast1","fade@yutFast2","inner@uTM@p","@Fd21@Fd42@Fd43FK4FK8@Fd4f","249 F","#stst2F1st2.jFN#FWF]cmf1F]FW-2F]cmf2F$FW",FBreview-F`.jpF)F`.jpF)F`-baFV.jFN#cmfFGnFPFGandarFbbusineFbstndFPdF]F`ordFTdFacm1Facm2","299 F","#FW2F1F`2.jFN#busistF]bsns1",FSst-2F]bsns2",FSst-3F]bsns3F$busist",FBreview-bsn.jpF)bsn.jpF)bsn-baFV.jFN#bsn","left activeFGnFTFGandarFbF`orFbstndFTd",FSnedFPdFabs1Fabs2Fabs3","399 F",FBsel-bsn2.jpF)bsn3.jpg)FGkv1F$F^1"F!F^1F[stan1"F!F^FQa#stan2","nav a#stnF]FM1","nav a#cmfFA1","nav a#bsnFGkvFQ1 FKa.FKaFK2.F$FM1"F!F`kv1F[com1"F!F`kvFQa#comF=FQ349 F","selectvar.html#bFe1"F!bFe1F[buss1"F!bFeFQa#buss2"F!bFe1-3F[buss3FA1-2FA1-3","449 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  2. Kaimi

    Kaimi Active Member

    Регистрация:
    23.08.2007
    Сообщения:
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    Одобрения:
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